Decimal.Add() Method in C#

Last Updated : 29 Jan, 2019
This method is used to add two specified decimal values.
Syntax: public static decimal Add (decimal a1, decimal a2); Parameters: a1: This parameter specifies the first value to add. a2: This parameter specifies the second value to add. Return Value: Decimal sum of a1 & a2.
Exceptions: This method will give OverflowException if the sum of a1 and a2 is less than smallest possible value of Decimal or greater than the largest possible value of Decimal. Below programs illustrate the use of Decimal.Add(Decimal, Decimal) Method Example 1: csharp 
// C# program to demonstrate the
// Decimal.Add(Decimal, Decimal) 
// Method
using System;
using System.Globalization;

class GFG {

    // Main Method
    public static void Main()
    {
        try {

            // Declaring the decimal
            // variables
            Decimal a1 = .01m;
            Decimal a2 = .03m;

            // adding the two Decimal value
            // using Add() method;
            Decimal value = Decimal.Add(a1, a2);

            // Display the sum
            Console.WriteLine("Decimal Sum : {0}",
                                           value);
        }

        catch (OverflowException e) 
        {
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}
Output: 
Decimal Sum : 0.04
Example 2: For OverflowException csharp 
// C# program to demonstrate the
// Decimal.Add(Decimal, Decimal)
// Method
using System;
using System.Globalization;

class GFG {

    // Main Method
    public static void Main()
    {
        try {

            // Declaring the decimal variables
            Decimal a1 = 1.01m;
            Decimal a2 = Decimal.MaxValue;

            // adding the two Decimal value
            // using Add() method;
            Decimal value = Decimal.Add(a1, a2);

            // Display the sum
            Console.WriteLine("Decimal Sum : {0}",
                                           value);
        }

        catch (OverflowException e) 
        {
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}
Output: 
Exception Thrown: System.OverflowException
Comment

Explore