A matrix is a set of numbers arranged in rows and columns to form a rectangular array.
Matrix Practice Problems Covering Core Concepts and Applications
Practice Questions on Matrices - Solved
Question 1: If (A+B)2 = A + 2AB + B,2 then what can we say about A and B? (Assume AB and BA exist.)
Solution:
(A+B)2 = (A+B) (A+B)
⇒ According to question,
⇒ A2 + AB + BA + B2 = A2 + 2AB + B2
⇒ AB+BA = 2AB
⇒ BA = AB⇒ So, we can say that A and B are commutative
Question 2: If A is an n x m matrix such that AB and BA are both defined, then the order of B is
Solution:
If A size is n x m and it is also given that AB is defined then,
⇒ An x m X Bm x ☐ = (AB)n x n
⇒ ☐ = nOR
⇒ B☐ x m X An x m = (AB)n x n
⇒ ☐ = n⇒ So, the size of the matrix B is m x n
Question 3: Under what conditions will the matrix equation A - B2 = (A - B) (A + B) be true?
Solution:
We are given, A2-B2 = (A-B) (A+B)
⇒ A2 - B2 = A2 + AB - BA + B2
⇒ AB - BA = 0
⇒ AB = BA⇒ So, we can say that A and B should be commutative
Question 4: If AB = A and BA = B, then show that A and B are idempotent matrices.
Solution:
We are given that,
AB = A
⇒ A(BA) = A
⇒ (AB)A = A
⇒ (A)A = A
⇒ A2 = A⇒ So, we can say that A is idempotent matrix
Similarly, we can prove that B is also an idempotent matrix.
Question 5: Show that the sum of two idempotent matrices A and B is idempotent if AB = BA = 0.
Solution:
We have been given that,
AB = BA = 0 and A2 = A and B2 = B
⇒ (A+B)2 = (A+B) (A+B)
⇒ (A+B)2 = A2 + AB + BA + B2
⇒ (A+B)2 = A2 + B2 {since, AB=BA=0}
⇒ (A+B)2 = A + B⇒ Hence, sum of two idempotent matrices A and B is idempotent if AB=BA=0
Question 6: Evaluate
Solution:
Since
\omega is the cube root of unity, we know that1+\omega+\omega^2=0 By applying C1 → C1 + C2 + C3
⇒\begin{vmatrix}1+\omega+\omega^2 & \omega & \omega^2\\\omega+\omega^2+1 & \omega^2 & 1\\\omega^2+1+\omega & 1 & \omega\end{vmatrix}
Now, we know since1+\omega+\omega^2=0 Above determinant is written as,
⇒\begin{vmatrix}0 & \omega & \omega^2\\0 & \omega^2 & 1\\0 & 1 & \omega\end{vmatrix}
⇒0 Hence, the value of the given determinant is 0
Question 7: Evaluate
Solution:
By applying R1 → R1 + R2 + R3
⇒
\Delta = \begin{vmatrix}a-b + (b-c) + (c-a) & m-n + (n-p) + (p-m) & x-y + (y-z) + (z-x)\\b-c & n-p & y-z\\c-a & p-m & z-x\end{vmatrix}
⇒\Delta = \begin{vmatrix}0 & 0 & 0\\b-c & n-p & y-z\\c-a & p-m & z-x\end{vmatrix}
⇒\Delta = 0
Question 8: If A is a symmetric matrix, then prove that adj A (the adjoint of A) is also symmetric.
Solution:
Let 'A' is a symmetric matrix, then AT = A
We know that,
⇒ (adj A)T = adj AT
⇒ (adj A)T = adj AHence, adj A is also a symmetric matrix
Question 9: Show that if A is a non-singular matrix, then det(A⁻¹) = (det(A))⁻¹
Solution:
We know that, |A-1| = 1 / |A|
⇒ A A-1 = In {where, I is an Identity matrix}
⇒ |A A-1| = |In|
⇒ |A| |A-1| = 1
⇒ |A-1| = 1 / |A|
⇒ |A|-1 = 1 / |A|Hence proved
Question 10: If A and B are n x n squared matrices and AB = 0 & |B| ≠ 0, then A = 0. State True or False.
Solution:
Since, AB = 0
By multiplying by I on both sides, {where, I is an identity matrix}
⇒ A B B-1 = 0 B-1
⇒ A I = 0
⇒ A = 0Hence the above statement is True.
Practice Questions on Matrices - Unsolved
Question 1: Find x so that
Question 2: Under what conditions is the matrix equation A - B2 = (A + B)? Is (A+B) true?
Question 3: Evaluate
Question 4: Evaluate
Question 5: Prove that
Question 6: Evaluate
Question 7: If a+b+c = 0, then solve the equation
Question 8: Prove that if A is idempotent and A ≠ I, then A is singular.
Question 9: Only a square, non-singular matrix possesses an inverse, which is unique. State True or False.
Question 10: If AB = 0, does it imply that it is necessary that BA = 0?