[Guido van Rossum]
>> def getline(filename, lineno):
> if lineno < 1:
> return ''
> lineno -= 1
> f = open(filename)
> for i, line in enumerate(f):
> if i == lineno:
> break
> else:
> line = ''
> f.close()
> return line
>> Challenge 1: do it faster.
>> Challenge 2: do it with less code.
>> Challenge 3: do it faster and with less code.
>> Rules: the semantics must be the same: always close the file, return
> '' for lineno out of range; lineno < 1 should not open the file.
I doubt it's faster and it's barely less code (I had to resist the urge to
add a try/finally), but here is the only decent variation I could come up
with:
def getline(filename, lineno):
line = ''
if lineno > 0:
lineno -= 1
f = open(filename)
for i, s in enumerate(f):
if i == lineno:
line = s
break
f.close()
return line
I'm ready to give up now. What's the fastest, smallest solution?
---
Patrick K. O'Brien
Orbtech
