1804 United States House of Representatives election in Ohio
Appearance
This article relies on a single source. (July 2026) |
October 9, 1804
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| Elections in Ohio |
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Incumbent, Democratic-Republican Jeremiah Morrow won the general election held on October 9, 1804 with 70 percent of the votes.
Results
[edit]| Party | Candidate | Votes | % | ||
|---|---|---|---|---|---|
| Democratic-Republican | Jeremiah Morrow (incumbent) | 4,101 | 70.20% | ||
| Federalist | Elias Langham | 1,718 | 29.41% | ||
| Democratic-Republican | Rufus Putnam | 23 | 0.39% | ||
| Total votes | 5,842 | 100.0% | |||
| Democratic-Republican hold | |||||
| District | Incumbent | Party | First elected |
Result | Candidates |
|---|---|---|---|---|---|
| Ohio at-large | Jeremiah Morrow | Democratic-Republican | 1803 | Incumbent re-elected. | √ Jeremiah Morrow (Democratic-Republican) 70.2% Elias Langham (Federalist) 29.4% Rufus Putnam 0.4% |
See also
[edit]References
[edit]- ↑ "A New Nation Votes - Ohio 1804 U.S. House of Representatives". elections.lib.tufts.edu.