1812 United States presidential election in Ohio

1812 United States presidential election in Ohio
← 1808 1812 1816 →
President before election; James Madison; Democratic-Republican	Elected President ; James Madison; Democratic-Republican

The 1812 United States presidential election in Ohio took place as part of the 1812 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio re-elected incumbent Democratic-Republican President James Madison over the other Democratic-Republican and Federalist supported candidate DeWitt Clinton. Madison won Ohio by a margin of 38.42%.

Results

1812 United States presidential election in Ohio^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	James Madison (incumbent)	7,420	69.21%	8
	Democratic–Republican Party	DeWitt Clinton	3,301	30.79%	0
Totals			10,721	100.0%	8

↑ While commonly labeled as the Federalist candidate, Clinton technically ran as a Democratic-Republican and was not nominated by the Federalist party itself, the latter simply deciding not to field a candidate. This did not prevent endorsements from state Federalist parties (such as in Pennsylvania), but he received the endorsement from the New York state Democratic-Republicans as well

↑ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved December 8, 2019.

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